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11.8 Data Type Storage Requirements
The storage requirements for table data on disk depend on several factors. Different storage engines represent data types and store raw data differently. Table data might be compressed, either for a column or an entire row, complicating the calculation of storage requirements for a table or column.
Despite differences in storage layout on disk, the internal MySQL APIs that communicate and exchange information about table rows use a consistent data structure that applies across all storage engines.
This section includes guidelines and information for the storage requirements for each data type supported by MySQL, including the internal format and size for storage engines that use a fixed-size representation for data types. Information is listed by category or storage engine.
The internal representation of a table has a maximum row size of
65,535 bytes, even if the storage engine is capable of supporting
larger rows. This figure excludes
BLOB
or
TEXT
columns, which contribute only
9 to 12 bytes toward this size. For
BLOB
and
TEXT
data, the information is
stored internally in a different area of memory than the row
buffer. Different storage engines handle the allocation and
storage of this data in different ways, according to the method
they use for handling the corresponding types. For more
information, see Chapter 16, Alternative Storage Engines, and
Section C.10.4, “Limits on Table Column Count and Row Size”.
InnoDB Table Storage Requirements
See Section 15.10, “InnoDB Row Formats” for information about
storage requirements for InnoDB
tables.
NDB
tables use
4-byte alignment; all
NDB
data storage is done in
multiples of 4 bytes. Thus, a column value that would
typically take 15 bytes requires 16 bytes in an
NDB
table. For example, in
NDB
tables, the
TINYINT
,
SMALLINT
,
MEDIUMINT
, and
INTEGER
(INT
) column types each require
4 bytes storage per record due to the alignment factor.
Each BIT(
column takes M
)M
bits of storage
space. Although an individual
BIT
column is
not 4-byte aligned,
NDB
reserves 4 bytes (32 bits)
per row for the first 1-32 bits needed for
BIT
columns, then another 4 bytes for bits
33-64, and so on.
While a NULL
itself does not require any
storage space, NDB
reserves 4
bytes per row if the table definition contains any columns
allowing NULL
, up to 32
NULL
columns. (If an NDB Cluster table is
defined with more than 32 NULL
columns up
to 64 NULL
columns, then 8 bytes per row
are reserved.)
Every table using the NDB
storage
engine requires a primary key; if you do not define a primary
key, a “hidden” primary key is created by
NDB
. This hidden primary key
consumes 31-35 bytes per table record.
You can use the ndb_size.pl Perl script to
estimate NDB
storage requirements.
It connects to a current MySQL (not NDB Cluster) database and
creates a report on how much space that database would require
if it used the NDB
storage engine.
See Section 22.4.28, “ndb_size.pl — NDBCLUSTER Size Requirement Estimator” for
more information.
Data Type | Storage Required |
---|---|
TINYINT |
1 byte |
SMALLINT |
2 bytes |
MEDIUMINT |
3 bytes |
INT ,
INTEGER |
4 bytes |
BIGINT |
8 bytes |
FLOAT( |
4 bytes if 0 <= p <= 24, 8 bytes if 25
<= p <= 53 |
FLOAT |
4 bytes |
DOUBLE [PRECISION] ,
REAL |
8 bytes |
DECIMAL( ,
NUMERIC( |
Varies; see following discussion |
BIT( |
approximately (M +7)/8 bytes |
Values for DECIMAL
(and
NUMERIC
) columns are represented
using a binary format that packs nine decimal (base 10) digits
into four bytes. Storage for the integer and fractional parts of
each value are determined separately. Each multiple of nine
digits requires four bytes, and the “leftover”
digits require some fraction of four bytes. The storage required
for excess digits is given by the following table.
Leftover Digits | Number of Bytes |
---|---|
0 | 0 |
1 | 1 |
2 | 1 |
3 | 2 |
4 | 2 |
5 | 3 |
6 | 3 |
7 | 4 |
8 | 4 |
For TIME
,
DATETIME
, and
TIMESTAMP
columns, the storage
required for tables created before MySQL 5.6.4 differs from
tables created from 5.6.4 on. This is due to a change in 5.6.4
that permits these types to have a fractional part, which
requires from 0 to 3 bytes.
Data Type | Storage Required Before MySQL 5.6.4 | Storage Required as of MySQL 5.6.4 |
---|---|---|
YEAR |
1 byte | 1 byte |
DATE |
3 bytes | 3 bytes |
TIME |
3 bytes | 3 bytes + fractional seconds storage |
DATETIME |
8 bytes | 5 bytes + fractional seconds storage |
TIMESTAMP |
4 bytes | 4 bytes + fractional seconds storage |
As of MySQL 5.6.4, storage for
YEAR
and
DATE
remains unchanged. However,
TIME
,
DATETIME
, and
TIMESTAMP
are represented
differently. DATETIME
is packed
more efficiently, requiring 5 rather than 8 bytes for the
nonfractional part, and all three parts have a fractional part
that requires from 0 to 3 bytes, depending on the fractional
seconds precision of stored values.
Fractional Seconds Precision | Storage Required |
---|---|
0 | 0 bytes |
1, 2 | 1 byte |
3, 4 | 2 bytes |
5, 6 | 3 bytes |
For example, TIME(0)
,
TIME(2)
,
TIME(4)
, and
TIME(6)
use 3, 4, 5, and 6 bytes,
respectively. TIME
and
TIME(0)
are equivalent and
require the same storage.
For details about internal representation of temporal values, see MySQL Internals: Important Algorithms and Structures.
In the following table, M
represents
the declared column length in characters for nonbinary string
types and bytes for binary string types.
L
represents the actual length in
bytes of a given string value.
Data Type | Storage Required |
---|---|
CHAR( |
The compact family of InnoDB row formats optimize storage for
variable-length character sets. See
COMPACT Row Format Storage Characteristics.
Otherwise, M ×
w bytes, <=
255, where
w is the number of bytes
required for the maximum-length character in the character
set. |
BINARY( |
M bytes, 0 <=
255 |
VARCHAR( ,
VARBINARY( |
L + 1 bytes if column values require 0
− 255 bytes, L + 2 bytes
if values may require more than 255 bytes |
TINYBLOB ,
TINYTEXT |
L + 1 bytes, where
L <
28 |
BLOB , TEXT |
L + 2 bytes, where
L <
216 |
MEDIUMBLOB ,
MEDIUMTEXT |
L + 3 bytes, where
L <
224 |
LONGBLOB ,
LONGTEXT |
L + 4 bytes, where
L <
232 |
ENUM(' |
1 or 2 bytes, depending on the number of enumeration values (65,535 values maximum) |
SET(' |
1, 2, 3, 4, or 8 bytes, depending on the number of set members (64 members maximum) |
Variable-length string types are stored using a length prefix
plus data. The length prefix requires from one to four bytes
depending on the data type, and the value of the prefix is
L
(the byte length of the string).
For example, storage for a
MEDIUMTEXT
value requires
L
bytes to store the value plus three
bytes to store the length of the value.
To calculate the number of bytes used to store a particular
CHAR
,
VARCHAR
, or
TEXT
column value, you must take
into account the character set used for that column and whether
the value contains multibyte characters. In particular, when
using a utf8
Unicode character set, you must
keep in mind that not all characters use the same number of
bytes. utf8mb3
and utf8mb4
character sets can require up to three and four bytes per
character, respectively. For a breakdown of the storage used for
different categories of utf8mb3
or
utf8mb4
characters, see
Section 10.9, “Unicode Support”.
VARCHAR
,
VARBINARY
, and the
BLOB
and
TEXT
types are variable-length
types. For each, the storage requirements depend on these
factors:
The actual length of the column value
The column's maximum possible length
The character set used for the column, because some character sets contain multibyte characters
For example, a VARCHAR(255)
column can hold a
string with a maximum length of 255 characters. Assuming that
the column uses the latin1
character set (one
byte per character), the actual storage required is the length
of the string (L
), plus one byte to
record the length of the string. For the string
'abcd'
, L
is 4 and
the storage requirement is five bytes. If the same column is
instead declared to use the ucs2
double-byte
character set, the storage requirement is 10 bytes: The length
of 'abcd'
is eight bytes and the column
requires two bytes to store lengths because the maximum length
is greater than 255 (up to 510 bytes).
The effective maximum number of bytes that
can be stored in a VARCHAR
or
VARBINARY
column is subject to
the maximum row size of 65,535 bytes, which is shared among all
columns. For a VARCHAR
column
that stores multibyte characters, the effective maximum number
of characters is less. For example,
utf8mb4
characters can require up to four
bytes per character, so a VARCHAR
column that uses the utf8mb4
character set
can be declared to be a maximum of 16,383 characters. See
Section C.10.4, “Limits on Table Column Count and Row Size”.
InnoDB
encodes fixed-length fields greater
than or equal to 768 bytes in length as variable-length fields,
which can be stored off-page. For example, a
CHAR(255)
column can exceed 768 bytes if the
maximum byte length of the character set is greater than 3, as
it is with utf8mb4
.
The NDB
storage engine supports
variable-width columns. This means that a
VARCHAR
column in an NDB Cluster
table requires the same amount of storage as would any other
storage engine, with the exception that such values are 4-byte
aligned. Thus, the string 'abcd'
stored in a
VARCHAR(50)
column using the
latin1
character set requires 8 bytes (rather
than 5 bytes for the same column value in a
MyISAM
table).
TEXT
and
BLOB
columns are implemented
differently in NDB
; each row in a
TEXT
column is made up of two separate parts.
One of these is of fixed size (256 bytes), and is actually
stored in the original table. The other consists of any data in
excess of 256 bytes, which is stored in a hidden table. The rows
in this second table are always 2000 bytes long. This means that
the size of a TEXT
column is 256 if
size
<= 256 (where
size
represents the size of the row);
otherwise, the size is 256 +
size
+ (2000 ×
(size
− 256) % 2000).
The size of an ENUM
object is
determined by the number of different enumeration values. One
byte is used for enumerations with up to 255 possible values.
Two bytes are used for enumerations having between 256 and
65,535 possible values. See Section 11.4.4, “The ENUM Type”.
The size of a SET
object is
determined by the number of different set members. If the set
size is N
, the object occupies
(
bytes,
rounded up to 1, 2, 3, 4, or 8 bytes. A
N
+7)/8SET
can have a maximum of 64
members. See Section 11.4.5, “The SET Type”.
MySQL stores geometry values using 4 bytes to indicate the SRID
followed by the WKB representation of the value. The
LENGTH()
function returns the
space in bytes required for value storage.
For descriptions of WKB and internal storage formats for spatial values, see Section 11.5.3, “Supported Spatial Data Formats”.
In general, the storage requirement for a
JSON
column is approximately the
same as for a LONGBLOB
or
LONGTEXT
column; that is, the space consumed
by a JSON document is roughly the same as it would be for the
document's string representation stored in a column of one
of these types. However, there is an overhead imposed by the
binary encoding, including metadata and dictionaries needed for
lookup, of the individual values stored in the JSON document.
For example, a string stored in a JSON document requires 4 to 10
bytes additional storage, depending on the length of the string
and the size of the object or array in which it is stored.
In addition, MySQL imposes a limit on the size of any JSON
document stored in a JSON
column such that it
cannot be any larger than the value of
max_allowed_packet
.
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