Rechercher une fonction PHP

debug_zval_dump

(PHP 4 >= 4.2.0, PHP 5, PHP 7)

debug_zval_dumpDumps a string representation of an internal zend value to output

Description

debug_zval_dump ( mixed $variable [, mixed $... ] ) : void

Dumps a string representation of an internal zend value to output.

PHP: debug_zval_dump - Manual Home of Manuel PHP  Contents Haut

Parameters

variable

The variable being evaluated.

PHP: debug_zval_dump - Manual Home of Manuel PHP  Contents Haut

Return Values

No value is returned.

PHP: debug_zval_dump - Manual Home of Manuel PHP  Contents Haut

Examples

Example #1 debug_zval_dump() example

<?php
$var1 
'Hello World';
$var2 '';

$var2 =& $var1;

debug_zval_dump(&$var1);
?>

The above example will output:

&string(11) "Hello World" refcount(3)

Note: Beware the refcount

The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump().

This behavior is further compounded when a variable is not passed to debug_zval_dump() by reference. To illustrate, consider a slightly modified version of the above example:

<?php
$var1 
'Hello World';
$var2 '';

$var2 =& $var1;

debug_zval_dump($var1); // not passed by reference, this time
?>

The above example will output:

string(11) "Hello World" refcount(1)

Why refcount(1)? Because a copy of $var1 is being made, when the function is called.

This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):

<?php
$var1 
'Hello World';

debug_zval_dump($var1);
?>

The above example will output:

string(11) "Hello World" refcount(2)

A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?

When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump()), PHP's engine optimizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made, but only at the moment of writing. This is known as "copy on write."

So, if debug_zval_dump() happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.

Find a PHP function

English translation

You have asked to visit this site in English. For now, only the interface is translated, but not all the content yet.

If you want to help me in translations, your contribution is welcome. All you need to do is register on the site, and send me a message asking me to add you to the group of translators, which will give you the opportunity to translate the pages you want. A link at the bottom of each translated page indicates that you are the translator, and has a link to your profile.

Thank you in advance.

Document created the 30/01/2003, last modified the 26/10/2018
Source of the printed document:https://www.gaudry.be/en/php-rf-debug-zval-dump.html

The infobrol is a personal site whose content is my sole responsibility. The text is available under CreativeCommons license (BY-NC-SA). More info on the terms of use and the author.

References

  1. View the html document Language of the document:fr Manuel PHP : http://php.net

These references and links indicate documents consulted during the writing of this page, or which may provide additional information, but the authors of these sources can not be held responsible for the content of this page.
The author This site is solely responsible for the way in which the various concepts, and the freedoms that are taken with the reference works, are presented here. Remember that you must cross multiple source information to reduce the risk of errors.

Contents Haut